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(x-3)(x+5)=x^2-7x-6
We move all terms to the left:
(x-3)(x+5)-(x^2-7x-6)=0
We get rid of parentheses
-x^2+(x-3)(x+5)+7x+6=0
We multiply parentheses ..
-x^2+(+x^2+5x-3x-15)+7x+6=0
We add all the numbers together, and all the variables
-1x^2+(+x^2+5x-3x-15)+7x+6=0
We get rid of parentheses
-1x^2+x^2+5x-3x+7x-15+6=0
We add all the numbers together, and all the variables
9x-9=0
We move all terms containing x to the left, all other terms to the right
9x=9
x=9/9
x=1
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